Exploding Dice 
[Jan. 10th, 201002:09 am]
Beemer

So here's a nifty thing I learned today.
In some RPGs, you roll exploding dice: if a die rolls its maximum value, you add that value and reroll, repeating as necessary. So what's the expectation value for such a die?
The expectation value for a normal Nsided die is = (1+2+...+N)/N = (N+1)/2.
For an exploding die, you just multiply that by N/(N1).
So a normal d6 rolls on average 7/2 = 3.5, and an exploding d6 rolls on average 7*6/5*2 = 4.2.
Keen!
(This comes from this "a mathematical analysis of exploding dice". I tried to do the general case analytically, but couldn't get the algebra to work out. I was never any good at that kind of math...) 

